two researchers are studying the decline of orangutan populations. in one study, a population of 784…

two researchers are studying the decline of orangutan populations. in one study, a population of 784 orangutans is expected to decrease at a rate of 25 orangutans per year. in a second study, the population of a group of 817 orangutans is expected to decrease at a rate of 36 per year. after how many years will the two populations be the same? the two populations will be the same after years.

two researchers are studying the decline of orangutan populations. in one study, a population of 784 orangutans is expected to decrease at a rate of 25 orangutans per year. in a second study, the population of a group of 817 orangutans is expected to decrease at a rate of 36 per year. after how many years will the two populations be the same? the two populations will be the same after years.

Answer

Explanation:

Step1: Set up equations

Let $x$ be the number of years. The first - population equation is $y_1 = 784−25x$, and the second - population equation is $y_2 = 817−36x$. When the two populations are the same, $y_1=y_2$, so $784 - 25x=817 - 36x$.

Step2: Solve for $x$

Add $36x$ to both sides of the equation: $784 - 25x+36x=817 - 36x+36x$, which simplifies to $784 + 11x=817$. Then subtract 784 from both sides: $784 + 11x-784=817 - 784$, getting $11x = 33$. Divide both sides by 11: $x=\frac{33}{11}=3$.

Answer:

3