two of the steps in the derivation of the quadratic formula are shown below. step 6: $\frac{b^{2}-4ac}{4a^{2}…

two of the steps in the derivation of the quadratic formula are shown below. step 6: $\frac{b^{2}-4ac}{4a^{2}}=(x + \frac{b}{2a})^{2}$ step 7: $\frac{pmsqrt{b^{2}-4ac}}{2a}=x+\frac{b}{2a}$ which operation is performed in the derivation of the quadratic formula moving from step 6 to step 7? subtracting $\frac{b}{2a}$ from both sides of the equation squaring both sides of the equation taking the square root of both sides of the equation taking the square root of the discriminant

two of the steps in the derivation of the quadratic formula are shown below. step 6: $\frac{b^{2}-4ac}{4a^{2}}=(x + \frac{b}{2a})^{2}$ step 7: $\frac{pmsqrt{b^{2}-4ac}}{2a}=x+\frac{b}{2a}$ which operation is performed in the derivation of the quadratic formula moving from step 6 to step 7? subtracting $\frac{b}{2a}$ from both sides of the equation squaring both sides of the equation taking the square root of both sides of the equation taking the square root of the discriminant

Answer

Explanation:

Step1: Analyze Step 6 and 7

In Step 6, we have $\frac{b^{2}-4ac}{4a^{2}}=(x + \frac{b}{2a})^{2}$. In Step 7, we get $\frac{\pm\sqrt{b^{2}-4ac}}{2a}=x+\frac{b}{2a}$.

Step2: Identify the operation

We take the square - root of both sides of the equation in Step 6. When we take the square root of the left - hand side $\frac{b^{2}-4ac}{4a^{2}}$, we get $\frac{\pm\sqrt{b^{2}-4ac}}{2a}$, and the right - hand side $(x+\frac{b}{2a})^{2}$ becomes $x+\frac{b}{2a}$.

Answer:

taking the square root of both sides of the equation