type the correct answer in each box. if necessary, use / for the fraction bar(s).\nfind the solution for…

type the correct answer in each box. if necessary, use / for the fraction bar(s).\nfind the solution for this system of equations.\n12x + 15y = 34\n-6x + 5y = 3\nx = \n\ny = \n

type the correct answer in each box. if necessary, use / for the fraction bar(s).\nfind the solution for this system of equations.\n12x + 15y = 34\n-6x + 5y = 3\nx = \n\ny = \n

Answer

Explanation:

Step1: Multiply the second - equation by 2

Multiply $-6x + 5y=3$ by 2 to get $-12x + 10y = 6$.

Step2: Add the new equation to the first equation

$(12x+15y)+(-12x + 10y)=34 + 6$. Combining like - terms: $12x-12x+15y + 10y=40$, which simplifies to $25y=40$. Then $y=\frac{40}{25}=\frac{8}{5}$.

Step3: Substitute $y$ into the second equation

Substitute $y = \frac{8}{5}$ into $-6x+5y = 3$. We have $-6x+5\times\frac{8}{5}=3$. $-6x + 8 = 3$. Subtract 8 from both sides: $-6x=3 - 8=-5$. Then $x=\frac{-5}{-6}=\frac{5}{6}$.

Answer:

$x=\frac{5}{6}$ $y=\frac{8}{5}$