type the correct answer in each box. use numerals instead of words. consider function h. h(x)=\begin{cases}3x…

type the correct answer in each box. use numerals instead of words. consider function h. h(x)=\begin{cases}3x - 4, & x < 0\\2x^{2}-3x + 10, & 0leq x < 4\\2^{x}, & xgeq4end{cases} what are the values of the function when (x = 0) and when (x = 4)? (h(0)=square) (h(4)=square)

type the correct answer in each box. use numerals instead of words. consider function h. h(x)=\begin{cases}3x - 4, & x < 0\\2x^{2}-3x + 10, & 0leq x < 4\\2^{x}, & xgeq4end{cases} what are the values of the function when (x = 0) and when (x = 4)? (h(0)=square) (h(4)=square)

Answer

Explanation:

Step1: Find $h(0)$

Since $x = 0$ and $0\leq x<4$, we use the formula $h(x)=2x^{2}-3x + 10$. Substitute $x = 0$ into it: $h(0)=2\times0^{2}-3\times0 + 10$. $h(0)=10$

Step2: Find $h(4)$

Since $x = 4$ and $x\geq4$, we use the formula $h(x)=2^{x}$. Substitute $x = 4$ into it: $h(4)=2^{4}$. $h(4)=16$

Answer:

$h(0)=10$ $h(4)=16$