use the diagram to complete the statement. given △jkl, sin(38°) equals cos(38°). cos(52°). tan(38°). tan(52°).

Explanation:

Step1: Recall co - function identity

In a right - triangle, for complementary angles $\alpha$ and $\beta$ ($\alpha+\beta = 90^{\circ}$), $\sin\alpha=\cos\beta$.

Step2: Identify complementary angles

Since $38^{\circ}+52^{\circ}=90^{\circ}$, $\sin(38^{\circ})=\cos(52^{\circ})$.

Answer:

$\cos(52^{\circ})$