use $f(x)=\frac{1}{2}x$ and $f^{-1}(x)=2x$ to solve the problems.\n$f(2)=square$\n$f^{-1}(1)=square$\n$f^{-1}…

Explanation:

Step1: Find $f(2)$

Substitute $x = 2$ into $f(x)=\frac{1}{2}x$. So $f(2)=\frac{1}{2}\times2$. $f(2)=1$

Step2: Find $f^{-1}(1)$

Substitute $x = 1$ into $f^{-1}(x)=2x$. So $f^{-1}(1)=2\times1$. $f^{-1}(1)=2$

Step3: Find $f^{-1}(f(2))$

First, we know $f(2) = 1$ from Step1. Then substitute $x = 1$ into $f^{-1}(x)$. Since $f^{-1}(x)=2x$, then $f^{-1}(f(2))=f^{-1}(1)=2\times1$. $f^{-1}(f(2))=2$

Answer:

$f(2)=1$ $f^{-1}(1)=2$ $f^{-1}(f(2))=2$