use the function $f(x)=2x^{3}-3x^{2}+7$ to complete the exercises. $f(-1)=square$ $f(1)=square$ $f(2)=square$

Explanation:

Step1: Substitute $x = - 1$ into $f(x)$

$f(-1)=2\times(-1)^3-3\times(-1)^2 + 7$ $=2\times(-1)-3\times1 + 7$ $=-2 - 3+7$ $=2$

Step2: Substitute $x = 1$ into $f(x)$

$f(1)=2\times1^3-3\times1^2 + 7$ $=2\times1-3\times1 + 7$ $=2 - 3+7$ $=6$

Step3: Substitute $x = 2$ into $f(x)$

$f(2)=2\times2^3-3\times2^2 + 7$ $=2\times8-3\times4 + 7$ $=16-12 + 7$ $=11$

Answer:

$f(-1)=2$ $f(1)=6$ $f(2)=11$