use the graph to estimate the x- and y-intercepts of the function and describe where the function is…

use the graph to estimate the x- and y-intercepts of the function and describe where the function is positive and negative.\nx-intercept(s): select choice\ny-intercept: select choice\npositive: when select choice\nnegative: when select choice

use the graph to estimate the x- and y-intercepts of the function and describe where the function is positive and negative.\nx-intercept(s): select choice\ny-intercept: select choice\npositive: when select choice\nnegative: when select choice

Answer

Explanation:

Step1: Identify x - intercepts

The x - intercepts are the points where the graph intersects the x - axis (where (y = 0)). From the graph (a parabola opening upwards), we can see that the graph intersects the x - axis at (x=-2) and (x = 2) (assuming the grid has integer coordinates, and the distance from the origin to the intersection points is 2 units). So the x - intercepts are ((-2,0)) and ((2,0)) or (x=-2) and (x = 2).

Step2: Identify y - intercept

The y - intercept is the point where the graph intersects the y - axis (where (x = 0)). From the graph, the vertex of the parabola (the lowest point) is at ((0,-4))? Wait, no, looking at the graph, when (x = 0), the y - coordinate of the point on the graph is (-4)? Wait, no, maybe I misread. Wait, the parabola is opening upwards, and the vertex is on the y - axis. Let's check the grid. If the vertex is at ((0, - 4))? No, maybe the y - intercept is at ((0,-4))? Wait, no, let's think again. Wait, the x - intercepts: let's assume the grid has each square as 1 unit. The graph crosses the x - axis at (x=-2) and (x = 2) (so x - intercepts are (-2) and (2)). The y - intercept is the point where (x = 0), so looking at the graph, when (x = 0), the y - value is (-4)? Wait, no, maybe the vertex is at ((0,-4)), so the y - intercept is ((0,-4))? Wait, no, the y - intercept is the value of (y) when (x = 0), so from the graph, the point on the y - axis is ((0,-4))? Wait, maybe I made a mistake. Wait, the graph is a parabola opening upwards, symmetric about the y - axis. Let's see the x - intercepts: when (y = 0), (x=-2) and (x = 2). When (x = 0), (y=-4) (so y - intercept is (-4)).

Step3: Determine where the function is positive

A function is positive when its graph is above the x - axis ((y>0)). For a parabola opening upwards with x - intercepts at (x=-2) and (x = 2), the graph is above the x - axis when (x<-2) or (x>2) (because outside the roots, the parabola is above the x - axis).

Step4: Determine where the function is negative

A function is negative when its graph is below the x - axis ((y < 0)). For the parabola, between the x - intercepts ((-2<x<2)), the graph is below the x - axis.

Answer:

x - intercept(s): (-2) and (2) (or ((-2,0)) and ((2,0))) y - intercept: (-4) (or ((0,-4))) positive: when (x < - 2) or (x>2) negative: when (-2<x<2)

(Note: The actual values may depend on the exact grid. If the grid has each square as 1 unit, and the x - intercepts are at (x=-2) and (x = 2), y - intercept at (y=-4), positive for (x < - 2) or (x>2), negative for (-2<x<2))