use proportions to solve the following problem. the water rate for a city in north carolina is $1.38 per 758…

use proportions to solve the following problem. the water rate for a city in north carolina is $1.38 per 758 gallons of water used. a) what is the water bill if a resident of that city uses 20,000 gallons? b) how many gallons of water can a customer use if the water bill is not to exceed $130? a) the water bill for using 20,000 gallons of water is $36.41. (type an integer or a decimal. round to the nearest cent as needed.) b) if the water bill is not to exceed $130, the customer can use a maximum of gallons of water. (round down to the nearest integer as needed.)

use proportions to solve the following problem. the water rate for a city in north carolina is $1.38 per 758 gallons of water used. a) what is the water bill if a resident of that city uses 20,000 gallons? b) how many gallons of water can a customer use if the water bill is not to exceed $130? a) the water bill for using 20,000 gallons of water is $36.41. (type an integer or a decimal. round to the nearest cent as needed.) b) if the water bill is not to exceed $130, the customer can use a maximum of gallons of water. (round down to the nearest integer as needed.)

Answer

Explanation:

Step1: Set up proportion for part a

Let $x$ be the water - bill for 20000 gallons. The proportion is $\frac{1.38}{758}=\frac{x}{20000}$.

Step2: Solve for $x$

Cross - multiply: $758x = 1.38\times20000$. Then $x=\frac{1.38\times20000}{758}=\frac{27600}{758}\approx36.41$.

Step3: Set up proportion for part b

Let $y$ be the number of gallons. The proportion is $\frac{1.38}{758}=\frac{130}{y}$.

Step4: Solve for $y$

Cross - multiply: $1.38y=130\times758$. Then $y = \frac{130\times758}{1.38}=\frac{98540}{1.38}\approx71405.8$. Rounding down, $y = 71405$.

Answer:

a) $36.41 b) 71405