use substitution to solve the system of equations.\n$3x + 4y = -3$\n$x + 2y = -1$

Explanation:

Step1: Solve for x from the second equation

From ( x + 2y = -1 ), we can express ( x ) as ( x = -1 - 2y ).

Step2: Substitute x into the first equation

Substitute ( x = -1 - 2y ) into ( 3x + 4y = -3 ): [ \begin{align*} 3(-1 - 2y) + 4y &= -3\ -3 - 6y + 4y &= -3\ -3 - 2y &= -3 \end{align*} ]

Step3: Solve for y

Add 3 to both sides: ( -2y = 0 ), so ( y = 0 ).

Step4: Substitute y back to find x

Substitute ( y = 0 ) into ( x = -1 - 2y ): ( x = -1 - 2(0) = -1 ).

Answer:

((-1, 0))