use synthetic division to solve $(2x^{3}+4x^{2}-35x + 15)div(x - 3)$. what is the quotient?\n$2x^{2}-2x…

use synthetic division to solve $(2x^{3}+4x^{2}-35x + 15)div(x - 3)$. what is the quotient?\n$2x^{2}-2x - 29+\frac{102}{x + 3}$\n$2x^{2}-2x - 29+\frac{102}{x - 3}$\n$2x^{3}+10x^{2}-5x$\n$2x^{2}+10x - 5$
Answer
Explanation:
Step1: Set up synthetic division
The divisor is $x - 3$, so we use $c=3$. The dividend coefficients are $2,4,-35,15$.
| 3 | 2 | 4 | -35 | 15 |
|---|---|---|---|---|
Step2: Bring down the first coefficient
Bring down the first coefficient 2.
| 3 | 2 | 4 | -35 | 15 |
|---|---|---|---|---|
| 2 |
Step3: Multiply and add
Multiply 3 by 2 to get 6, add to 4 to get 10.
| 3 | 2 | 4 | -35 | 15 |
|---|---|---|---|---|
| 6 | ||||
| 2 | 10 |
Step4: Repeat multiplication - addition
Multiply 3 by 10 to get 30, add to - 35 to get - 5.
| 3 | 2 | 4 | -35 | 15 |
|---|---|---|---|---|
| 6 | 30 | |||
| 2 | 10 | -5 |
Step5: One - more multiplication - addition
Multiply 3 by - 5 to get - 15, add to 15 to get 0.
| 3 | 2 | 4 | -35 | 15 |
|---|---|---|---|---|
| 6 | 30 | -15 | ||
| 2 | 10 | -5 | 0 | |
| The numbers 2, 10, - 5 are the coefficients of the quotient polynomial. The quotient is a quadratic polynomial. The quotient is $2x^{2}+10x - 5$. |
Answer:
$2x^{2}+10x - 5$