use synthetic division to solve $(4x^{3}-3x^{2}+5x + 6)div(x + 6)$. what is the quotient?\n$4x^{2}-27x +…

use synthetic division to solve $(4x^{3}-3x^{2}+5x + 6)div(x + 6)$. what is the quotient?\n$4x^{2}-27x + 167-\frac{996}{x - 6}$\n$4x^{2}+21x + 131+\frac{792}{x + 6}$\n$4x^{2}+21x + 131+\frac{792}{x - 6}$\n$4x^{2}-27x + 167-\frac{996}{x + 6}$
Answer
Explanation:
Step1: Set up synthetic division
For $(4x^{3}-3x^{2}+5x + 6)\div(x + 6)$, we use - 6 (since $x+6=x-(-6)$) in the synthetic - division setup. The coefficients of the dividend are 4, - 3, 5, 6.
Step2: Bring down the first coefficient
Bring down the first coefficient 4.
Step3: Multiply and add
Multiply - 6 by 4 to get - 24. Add - 24 to - 3: $-3+( - 24)=-27$.
Step4: Multiply and add again
Multiply - 6 by - 27 to get 162. Add 162 to 5: $5 + 162=167$.
Step5: Multiply and add one more time
Multiply - 6 by 167 to get - 1002. Add - 1002 to 6: $6+( - 1002)=-996$. The quotient is $4x^{2}-27x + 167$ and the remainder is - 996. So the result of the division is $4x^{2}-27x + 167-\frac{996}{x + 6}$.
Answer:
$4x^{2}-27x + 167-\frac{996}{x + 6}$