use the zero product property to find the solutions to the equation $x^{2}-13x + 30 = 0$.\n$x=-10$ or…

use the zero product property to find the solutions to the equation $x^{2}-13x + 30 = 0$.\n$x=-10$ or $x=-3$\n$x=-10$ or $x = 3$\n$x=-3$ or $x = 10$\n$x = 3$ or $x = 10$
Answer
Explanation:
Step1: Factor the quadratic equation
We need to find two numbers that multiply to 30 and add up to 13. The numbers are 3 and 10. So, $x^{2}-13x + 30=(x - 3)(x - 10)=0$.
Step2: Apply the zero - product property
If $ab = 0$, then either $a = 0$ or $b = 0$. So, if $(x - 3)(x - 10)=0$, then $x-3=0$ or $x - 10=0$.
Step3: Solve for x
For $x-3=0$, we get $x=3$. For $x - 10=0$, we get $x=10$.
Answer:
$x = 3$ or $x = 10$