using the quadratic formula to solve 7x² - x = 7, what are the values of x?\n$\frac{1pmsqrt{195}i}{14}$\n$\fr…

Explanation:

Step1: Rewrite the equation in standard form

First, rewrite $7x^{2}-x = 7$ as $7x^{2}-x - 7=0$. For a quadratic equation $ax^{2}+bx + c = 0$, here $a = 7$, $b=-1$, $c=-7$.

Step2: Calculate the discriminant

The discriminant $\Delta=b^{2}-4ac$. Substitute $a = 7$, $b=-1$, $c=-7$ into it. So $\Delta=(-1)^{2}-4\times7\times(-7)=1 + 196=197$.

Step3: Apply the quadratic formula

The quadratic formula is $x=\frac{-b\pm\sqrt{\Delta}}{2a}$. Substitute $a = 7$, $b=-1$, $\Delta = 197$ into it. We get $x=\frac{-(-1)\pm\sqrt{197}}{2\times7}=\frac{1\pm\sqrt{197}}{14}$.

Answer:

B. $\frac{1\pm\sqrt{197}}{14}$