what is the value of $(-14^{0})^{-2}$?\n- $\frac{1}{196}$\n- $\frac{1}{196}$\n- 0\n- 1

Explanation:

Step1: Evaluate the exponent inside the parentheses

According to the zero - exponent rule, any non - zero number to the power of 0 is 1. So, $14^{0}=1$, then $- 14^{0}=-1$.

Step2: Calculate the negative exponent

We have $(-1)^{-2}$. By the negative - exponent rule $a^{-n}=\frac{1}{a^{n}}$, when $a = - 1$ and $n = 2$, we get $(-1)^{-2}=\frac{1}{(-1)^{2}}$.

Step3: Evaluate the square

$(-1)^{2}=(-1)\times(-1) = 1$, so $\frac{1}{(-1)^{2}}=\frac{1}{1}=1$.

Answer:

1