what is the value of $m^{2}-2mn + n^{2}$ for $m=-2$ and $n = 4$?\n-36\n-4\n4\n36
what is the value of $m^{2}-2mn + n^{2}$ for $m=-2$ and $n = 4$?\n-36\n-4\n4\n36
Answer
Explanation:
Step1: Substitute values
Substitute (m = - 2) and (n = 4) into (m^{2}-2mn + n^{2}). [(-2)^{2}-2\times(-2)\times4+4^{2}]
Step2: Calculate each term
Calculate each part: ((-2)^{2}=4), (-2\times(-2)\times4 = 16), (4^{2}=16). [4 + 16+16]
Step3: Sum up
Add the results together: (4+16 + 16=36).
Answer:
36