what is the value of 36x - 8y² when x = 3 and y = -6?\na. -288\nb. -180\nc. 1,200\nd. 3,600

Explanation:

Step1: Substitute x value

Substitute $x = 3$ into $36x-8y^{2}$, we get $36\times3-8y^{2}=108 - 8y^{2}$.

Step2: Substitute y value

Substitute $y=-6$ into $108 - 8y^{2}$. First calculate $y^{2}=(-6)^{2}=36$. Then $8y^{2}=8\times36 = 288$.

Step3: Calculate the result

Calculate $108-288=-180$.

Answer:

B. -180