which value must be added to the expression $x^{2}+12x$ to make it a perfect - square trinomial?\n6\n36\n72\n…
which value must be added to the expression $x^{2}+12x$ to make it a perfect - square trinomial?\n6\n36\n72\n144
Answer
Explanation:
Step1: Recall the formula for perfect - square trinomial
For a quadratic expression of the form $x^{2}+bx$, to make it a perfect - square trinomial, we add $\left(\frac{b}{2}\right)^{2}$.
Step2: Identify the value of $b$
In the given expression $x^{2}+12x$, $b = 12$.
Step3: Calculate the value to be added
We calculate $\left(\frac{b}{2}\right)^{2}=\left(\frac{12}{2}\right)^{2}=6^{2}=36$.
Answer:
B. 36