which value must be added to the expression $x^{2}+16x$ to make it a perfect - square trinomial?\n8\n32\n64\n…
which value must be added to the expression $x^{2}+16x$ to make it a perfect - square trinomial?\n8\n32\n64\n256
Answer
Explanation:
Step1: Recall the formula for perfect - square trinomial
For a quadratic expression of the form (x^{2}+bx), to make it a perfect - square trinomial, we add ((\frac{b}{2})^{2}). Here (b = 16).
Step2: Calculate the value to be added
Substitute (b = 16) into ((\frac{b}{2})^{2}). We get ((\frac{16}{2})^{2}=8^{2}=64).
Answer:
C. 64