what is the value of the discriminant, $b^{2}-4ac$, for the quadratic equation $0 = -2x^{2}-3x + 8$, and…

what is the value of the discriminant, $b^{2}-4ac$, for the quadratic equation $0 = -2x^{2}-3x + 8$, and what does it mean about the number of real solutions the equation has?\nthe discriminant is -55, so the equation has 2 real solutions.\nthe discriminant is -55, so the equation has no real solutions.\nthe discriminant is 73, so the equation has 2 real solutions.\nthe discriminant is 73, so the equation has no real solutions.

what is the value of the discriminant, $b^{2}-4ac$, for the quadratic equation $0 = -2x^{2}-3x + 8$, and what does it mean about the number of real solutions the equation has?\nthe discriminant is -55, so the equation has 2 real solutions.\nthe discriminant is -55, so the equation has no real solutions.\nthe discriminant is 73, so the equation has 2 real solutions.\nthe discriminant is 73, so the equation has no real solutions.

Answer

Answer:

C. The discriminant is 73, so the equation has 2 real solutions.

Explanation:

Step1: Identify a, b, c values

For the quadratic equation $0=-2x^{2}-3x + 8$, we have $a=-2$, $b=-3$, $c = 8$.

Step2: Calculate the discriminant

Using the formula $\Delta=b^{2}-4ac$, substitute the values: $\Delta=(-3)^{2}-4\times(-2)\times8=9 + 64=73$.

Step3: Determine number of real - solutions

Since $\Delta = 73>0$, the quadratic equation has 2 real solutions.