what is the value of y in the equation 6.4x + 2.8y = 44.4, when x = 3?\n○ y = 5\n○ y = 6\n○ y = 8\n○ y = 9

Explanation:

Step1: Substitute (x = 3) into the equation

Substitute (x = 3) into (6.4x+2.8y = 44.4). We get (6.4\times3+2.8y=44.4). Calculate (6.4\times3 = 19.2), so the equation becomes (19.2 + 2.8y=44.4).

Step2: Isolate the term with (y)

Subtract (19.2) from both sides of the equation: (2.8y=44.4 - 19.2). Calculate (44.4-19.2 = 25.2), so (2.8y=25.2).

Step3: Solve for (y)

Divide both sides of the equation (2.8y = 25.2) by (2.8), (y=\frac{25.2}{2.8}). Since (\frac{25.2}{2.8}=\frac{252}{28}=9).

Answer:

(y = 9)