what is the value of x in the equation 7x + 2y = 48, when y = 3?\no x = 6\no x = 7\no x = 8\no x = 9

Explanation:

Step1: Substitute y value

Substitute (y = 3) into the equation (7x+2y = 48), we get (7x+2\times3=48). So, (7x + 6=48).

Step2: Isolate the term with x

Subtract 6 from both sides of the equation: (7x+6 - 6=48 - 6). This gives (7x=42).

Step3: Solve for x

Divide both sides of the equation by 7: (\frac{7x}{7}=\frac{42}{7}). So, (x = 6).

Answer:

A. (x = 6)