if $f(x)=1 - x$, which value is equivalent to $|f(i)|$?\n0\n1\n$sqrt{2}$\n$sqrt{-1}$
if $f(x)=1 - x$, which value is equivalent to $|f(i)|$?\n0\n1\n$sqrt{2}$\n$sqrt{-1}$
Answer
Answer:
C. $\sqrt{2}$
Explanation:
Step1: Find $f(i)$
Substitute $x = i$ into $f(x)=1 - x$. So $f(i)=1 - i$.
Step2: Calculate $|f(i)|$
For a complex - number $z=a + bi$, the modulus $|z|=\sqrt{a^{2}+b^{2}}$. Here $a = 1$ and $b=-1$ for $z = 1 - i$. Then $|f(i)|=\sqrt{1^{2}+(-1)^{2}}=\sqrt{1 + 1}=\sqrt{2}$.