what is the value of $\frac{6}{x}+2x^{2}$, when $x = 3$?\n8\n11\n14\n20

what is the value of $\frac{6}{x}+2x^{2}$, when $x = 3$?\n8\n11\n14\n20

what is the value of $\frac{6}{x}+2x^{2}$, when $x = 3$?\n8\n11\n14\n20

Answer

Explanation:

Step1: Substitute x = 3 into the first term

Substitute (x = 3) into (\frac{6}{x}), we get (\frac{6}{3}=2).

Step2: Substitute x = 3 into the second term

Substitute (x = 3) into (2x^{2}), we have (2\times3^{2}=2\times9 = 18).

Step3: Add the two results

Add the results of the two - steps: (2 + 18=20).

Answer:

20