what is the value of k?\n$\frac{1}{2}k + 6 = 4k - 8$\n$k=-4$\n$k=-3$\n$k = 3$\n$k = 4$

what is the value of k?\n$\frac{1}{2}k + 6 = 4k - 8$\n$k=-4$\n$k=-3$\n$k = 3$\n$k = 4$

what is the value of k?\n$\frac{1}{2}k + 6 = 4k - 8$\n$k=-4$\n$k=-3$\n$k = 3$\n$k = 4$

Answer

Explanation:

Step1: Move terms with k to one - side

Subtract $\frac{1}{2}k$ from both sides: $6 = 4k-\frac{1}{2}k - 8$.

Step2: Combine like - terms

$6=\left(4-\frac{1}{2}\right)k - 8$, and $4-\frac{1}{2}=\frac{8 - 1}{2}=\frac{7}{2}$, so $6=\frac{7}{2}k - 8$.

Step3: Move the constant term to the other side

Add 8 to both sides: $6 + 8=\frac{7}{2}k$, so $14=\frac{7}{2}k$.

Step4: Solve for k

Multiply both sides by $\frac{2}{7}$: $k = 14\times\frac{2}{7}=4$.

Answer:

D. $k = 4$