what is the value of x?\no $\frac{1}{3}sqrt{2}$ units\no $\frac{1}{2}sqrt{3}$ units\no $2sqrt{3}$ units\no…
what is the value of x?\no $\frac{1}{3}sqrt{2}$ units\no $\frac{1}{2}sqrt{3}$ units\no $2sqrt{3}$ units\no $3sqrt{2}$ units
Answer
Explanation:
Step1: Identify the right - angled triangle
The given figure has a right - angled triangle with two legs of length 3.
Step2: Apply the Pythagorean theorem
For a right - angled triangle with legs (a) and (b) and hypotenuse (c), (c=\sqrt{a^{2}+b^{2}}). Here (a = 3) and (b = 3), so (x=\sqrt{3^{2}+3^{2}}).
Step3: Calculate the value of (x)
[ \begin{align*} x&=\sqrt{9 + 9}\ &=\sqrt{18}\ &=\sqrt{9\times2}\ &=3\sqrt{2} \end{align*} ]
Answer:
(3\sqrt{2}) units