what is the value of r of the geometric series?\n sum_{n = 1}^{3}1.3(0.8)^{n - 1} \n0.8\n1.3\n3.0\n3.2
what is the value of r of the geometric series?\n sum_{n = 1}^{3}1.3(0.8)^{n - 1} \n0.8\n1.3\n3.0\n3.2
Answer
Explanation:
Step1: Recall geometric - series formula
The general form of a geometric series is $\sum_{n = 1}^{\infty}a\cdot r^{n - 1}$, where $a$ is the first - term and $r$ is the common ratio.
Step2: Identify $r$ in the given series
The given series is $\sum_{n = 1}^{3}1.3(0.8)^{n - 1}$. Comparing it with the general form $\sum_{n = 1}^{\infty}a\cdot r^{n - 1}$, we can see that $r = 0.8$.
Answer:
A. 0.8