what value of k makes the equation true?\n$(5a^{2}b^{3})(6a^{k}b)=30a^{6}b^{4}$\no 2\no 3\no 4\no 8

Explanation:

Step1: Multiply the left - hand side terms

When multiplying two terms with the same base, we add the exponents. So, ((5a^{2}b^{3})(6a^{k}b)=(5\times6)a^{2 + k}b^{3+1}=30a^{2 + k}b^{4}).

Step2: Equate the exponents of 'a'

Since ((5a^{2}b^{3})(6a^{k}b)=30a^{6}b^{4}), we set the exponents of (a) equal to each other. That is, (2 + k=6).

Step3: Solve for (k)

Subtract 2 from both sides of the equation (2 + k=6). We get (k=6 - 2=4).

Answer:

4