what value of k makes the equation true?\n$(5a^{2}b^{3})(6a^{k}b)=30a^{6}b^{4}$\n○ 2\n○ 3\n○ 4\n○ 8

Explanation:

Step1: Multiply coefficients and like terms

$(5a^2b^3)(6a^kb) = (5\times6)a^{2+k}b^{3+1} = 30a^{2+k}b^4$

Step2: Equate exponents of $a$

Set $2+k = 6$

Step3: Solve for $k$

$k = 6 - 2 = 4$

Answer:

4 (Option C)