what value of g makes the equation true?\n$(x + 7)(x - 4)=x^{2}+gx - 28$\n-11\n-3\n3\n11
what value of g makes the equation true?\n$(x + 7)(x - 4)=x^{2}+gx - 28$\n-11\n-3\n3\n11
Answer
Explanation:
Step1: Expand the left - hand side
Use the FOIL method: ((x + 7)(x - 4)=x\times x+x\times(-4)+7\times x + 7\times(-4)) [ \begin{align*} &=x^{2}-4x + 7x-28\ &=x^{2}+(7 - 4)x-28\ &=x^{2}+3x-28 \end{align*} ]
Step2: Compare with the right - hand side
Since ((x + 7)(x - 4)=x^{2}+gx-28) and ((x + 7)(x - 4)=x^{2}+3x-28), then by comparing the coefficients of (x), we have (g = 3)
Answer:
3