what is the value of the product (3 - 2i)(3 + 2i)?\n5\n9 + 4i\n9 - 4i\n13

Explanation:

Step1: Apply difference - of - squares formula

We know that $(a - b)(a + b)=a^{2}-b^{2}$. Here $a = 3$ and $b = 2i$. So, $(3 - 2i)(3 + 2i)=3^{2}-(2i)^{2}$.

Step2: Calculate the squares

$3^{2}=9$ and $(2i)^{2}=4i^{2}$. Since $i^{2}=-1$, then $4i^{2}=4\times(-1)=-4$.

Step3: Subtract the results

$9-( - 4)=9 + 4=13$.

Answer:

13