what is the value of the product (3 - 2i)(3 + 2i)?\no 5\no 9 + 4i\no 9 - 4i\no 13

Explanation:

Step1: Apply difference - of - squares formula

$(a - b)(a + b)=a^{2}-b^{2}$. Here $a = 3$ and $b = 2i$. So, $(3 - 2i)(3 + 2i)=3^{2}-(2i)^{2}$.

Step2: Calculate squares

$3^{2}=9$ and $(2i)^{2}=4i^{2}$. Since $i^{2}=-1$, then $(2i)^{2}=4\times(-1)=-4$.

Step3: Substitute and simplify

$3^{2}-(2i)^{2}=9-(-4)=9 + 4=13$.

Answer:

D. 13