what value of x is in the solution set of 3(x - 4) ≥ 5x + 2?\n-10\n-5\n5\n10

Explanation:

Step1: Expand the left - hand side

$3(x - 4)=3x-12$, so the inequality becomes $3x - 12\geq5x + 2$.

Step2: Move the $x$ terms to one side

Subtract $3x$ from both sides: $3x-3x - 12\geq5x-3x + 2$, which simplifies to $-12\geq2x + 2$.

Step3: Move the constant terms to one side

Subtract 2 from both sides: $-12 - 2\geq2x+2 - 2$, resulting in $-14\geq2x$.

Step4: Solve for $x$

Divide both sides by 2: $\frac{-14}{2}\geq\frac{2x}{2}$, so $x\leq - 7$.

Answer:

A. -10