what value of x is in the solution set of the inequality 9(2x + 1) < 9x - 18? -4 -3 -2 -1

Explanation:

Step1: Expand the left - hand side

$9(2x + 1)=18x+9$, so the inequality becomes $18x + 9<9x - 18$.

Step2: Move the terms with $x$ to one side

Subtract $9x$ from both sides: $18x-9x + 9<9x-9x - 18$, which simplifies to $9x+9<-18$.

Step3: Move the constant to the other side

Subtract 9 from both sides: $9x+9 - 9<-18 - 9$, resulting in $9x<-27$.

Step4: Solve for $x$

Divide both sides by 9: $\frac{9x}{9}<\frac{-27}{9}$, so $x < - 3$.

Answer:

A. - 4