what value of x is in the solution set of the inequality 2(3x - 1) ≥ 4x - 6?\n-10\n-5\n-3\n-1

Explanation:

Step1: Expand the left - hand side

$2(3x - 1)=6x-2$, so the inequality becomes $6x - 2\geq4x - 6$.

Step2: Move the terms with x to one side

Subtract $4x$ from both sides: $6x-4x - 2\geq4x-4x - 6$, which simplifies to $2x - 2\geq - 6$.

Step3: Move the constant terms to one side

Add 2 to both sides: $2x-2 + 2\geq - 6+2$, resulting in $2x\geq - 4$.

Step4: Solve for x

Divide both sides by 2: $\frac{2x}{2}\geq\frac{-4}{2}$, so $x\geq - 2$.

Answer:

D. -1