what is the y - value of the solution to the system of equations?\n3x + 5y = 1\n7x + 4y = - 13\n-3\n-1\n2\n5

Explanation:

Step1: Multiply equations for elimination

Multiply the first equation $3x + 5y=1$ by 7 and the second equation $7x + 4y=-13$ by 3. The first - new equation is $21x+35y = 7$ (since $7\times(3x + 5y)=7\times1$), and the second - new equation is $21x+12y=-39$ (since $3\times(7x + 4y)=3\times(-13)$).

Step2: Subtract equations to eliminate x

Subtract the second - new equation from the first - new equation: $(21x + 35y)-(21x + 12y)=7-(-39)$ $21x+35y - 21x - 12y=7 + 39$ $23y=46$.

Step3: Solve for y

Divide both sides of the equation $23y = 46$ by 23: $y=\frac{46}{23}=2$.

Answer:

2