what is the value of $sqrt{16}$?

Explanation:

Step1: Recall square - root definition

The square - root of a number (x), (\sqrt{x}), is a value (y) such that (y^2=x). We need to find a number (y) where (y^2 = 16).

Step2: Find the number

We know that (4\times4 = 16) and ((- 4)\times(-4)=16). But when we write (\sqrt{16}), by convention, we mean the principal (non - negative) square root. So (\sqrt{16}=4).

Answer:

4