what is the value of $sqrt{49}$?

Explanation:

Step1: Recall square - root definition

The square - root of a number (x), (\sqrt{x}), is a value (y) such that (y^2=x). We need to find a number (y) where (y^2 = 49).

Step2: Find the number

We know that (7\times7 = 49) and ((- 7)\times(-7)=49). In the case of the principal square - root (denoted by (\sqrt{x}) where (x\geq0)), the value is the non - negative root. So (\sqrt{49}=7).

Answer:

7