a vector has an x - component of -1.55 m, and a y - component of 3.22 m. find the magnitude of the vector. ? m

Explanation:

Step1: Recall magnitude formula

The magnitude $R$ of a vector with $x -$component $A_x$ and $y -$component $A_y$ is given by $R=\sqrt{A_x^{2}+A_y^{2}}$.

Step2: Substitute given values

Here, $A_x=- 1.55$ m and $A_y = 3.22$ m. So $R=\sqrt{(-1.55)^{2}+(3.22)^{2}}$. First, calculate $(-1.55)^{2}=2.4025$ and $(3.22)^{2}=10.3684$. Then $A_x^{2}+A_y^{2}=2.4025 + 10.3684=12.7709$. So $R=\sqrt{12.7709}\approx3.57$ m.

Answer:

$3.57$ m