what is the vertex of the graph of y = 3(x - 4)^2+2?\na (-4, 2)\nb (-4, -2)\nc (4, -2)\nd (4, 2)

Explanation:

Step1: Recall vertex - form of a parabola

The vertex - form of a parabola is $y=a(x - h)^{2}+k$, where the vertex is the point $(h,k)$.

Step2: Identify $h$ and $k$ values

For the equation $y = 3(x - 4)^{2}+2$, we have $h = 4$ and $k=2$.

Answer:

D. $(4,2)$