what is the volume of a sphere with a radius of 5.9 in, rounded to the nearest tenth of a cubic inch?

what is the volume of a sphere with a radius of 5.9 in, rounded to the nearest tenth of a cubic inch?

what is the volume of a sphere with a radius of 5.9 in, rounded to the nearest tenth of a cubic inch?

Answer

Explanation:

Step1: Recall the formula for the volume of a sphere

The formula for the volume (V) of a sphere is (V=\frac{4}{3}\pi r^{3}), where (r) is the radius of the sphere.

Step2: Substitute the given radius into the formula

Given (r = 5.9) in. Then (V=\frac{4}{3}\pi(5.9)^{3}). First, calculate ((5.9)^{3}=5.9\times5.9\times5.9 = 205.379). Then (V=\frac{4}{3}\pi\times205.379). (\frac{4}{3}\times205.379=273.83866\cdots). So (V = 273.83866\cdots\times\pi). Taking (\pi\approx3.14159), we have (V\approx273.83866\times3.14159\approx850.9).

Answer:

(850.9) cubic inches