write $z = -6i$ in polar form.\n(1 point)\n$\\bigcirc$ $z = 6\\mathrm{cis}\\frac{3\\pi}{2}$\n$\\bigcirc$ $z…

Explanation:

Step1: Find modulus of $z$

For $z = a + bi$, modulus $r = \sqrt{a^2 + b^2}$. Here $a=0, b=-6$, so: $r = \sqrt{0^2 + (-6)^2} = \sqrt{36} = 6$

Step2: Find argument of $z$

$z=-6i$ lies on negative imaginary axis, so $\theta = \frac{3\pi}{2}$.

Step3: Write polar form

Polar form is $r\cis\theta$, so substitute $r=6, \theta=\frac{3\pi}{2}$.

Answer:

$z = 6\cis \frac{3\pi}{2}$