write the following expression without negative exponents and without parentheses. (-6x)^{-2}

Answer:

$\frac{1}{36x^{2}}$

Explanation:

Step1: Use negative exponent rule

$$a^{-n}=\frac{1}{a^{n}}$$ So, $(-6x)^{-2}=\frac{1}{(-6x)^{2}}$

Step2: Expand the denominator

$$(-6x)^{2}=(-6)^{2}\times x^{2}=36x^{2}$$ So, $\frac{1}{(-6x)^{2}}=\frac{1}{36x^{2}}$