write the following expression without negative exponents and without parentheses. (4x)^{-3}

Answer:

$\frac{1}{64x^{3}}$

Explanation:

Step1: Apply the negative exponent rule

$$(4x)^{-3}=\frac{1}{(4x)^{3}}$$

Step2: Expand the denominator

$$(4x)^{3}=4^{3}\cdot x^{3}=64x^{3}$$

Step3: Combine the results

$$\frac{1}{(4x)^{3}}=\frac{1}{64x^{3}}$$