write and graph a linear equation in standard form and/or slope - intercept form.\n7) ( 5y = 3x )\n8) ( 3x…

write and graph a linear equation in standard form and/or slope - intercept form.\n7) ( 5y = 3x )\n8) ( 3x - y = 14 )\n9) a line has a slope of 7 and passes through the point ( (0,-10) ). what is its equation in slope - intercept form? graph the line.\n10) there is a line that includes the point ( (-3,-2) ) and has a slope of 2. what is its equation in slope - intercept form? graph the line.
Answer
Explanation:
Step1: Recall the slope - intercept form
The slope - intercept form of a line is (y = mx + b), where (m) is the slope and (b) is the (y) - intercept.
Step2: Identify the slope and (y) - intercept
Given that the slope (m = 7) and the line passes through the point ((0,-10)). For a line (y=mx + b), when (x = 0), (y=b). So, (b=-10).
Step3: Write the equation
Substitute (m = 7) and (b=-10) into the slope - intercept form (y=mx + b). We get (y = 7x-10).
Answer:
(y = 7x - 10)