in the xy - plane, line p has a slope of - 5/3 and an x - intercept of (-6,0). what is the y - coordinate of…

Explanation:

Step1: Recall the slope - intercept form

The equation of a line is $y = mx + b$, where $m$ is the slope and $b$ is the y - intercept. We know $m=-\frac{5}{3}$, so the line is $y =-\frac{5}{3}x + b$.

Step2: Substitute the x - intercept point

The x - intercept is the point $(-6,0)$. Substitute $x=-6$ and $y = 0$ into the equation $y=-\frac{5}{3}x + b$. We get $0=-\frac{5}{3}\times(-6)+b$.

Step3: Solve for b

First, calculate $-\frac{5}{3}\times(-6)=10$. Then the equation becomes $0 = 10 + b$. Subtracting 10 from both sides gives $b=-10$.

Answer:

$-10$