if you are given the graph of $h(x)=log_6 x$, how could you graph $m(x)=log_6(x + 3)$?\ntranslate each point…

if you are given the graph of $h(x)=log_6 x$, how could you graph $m(x)=log_6(x + 3)$?\ntranslate each point of the graph of $h(x)$ 3 units up.\ntranslate each point of the graph of $h(x)$ 3 units down.\ntranslate each point of the graph of $h(x)$ 3 units right.\ntranslate each point of the graph of $h(x)$ 3 units left.

if you are given the graph of $h(x)=log_6 x$, how could you graph $m(x)=log_6(x + 3)$?\ntranslate each point of the graph of $h(x)$ 3 units up.\ntranslate each point of the graph of $h(x)$ 3 units down.\ntranslate each point of the graph of $h(x)$ 3 units right.\ntranslate each point of the graph of $h(x)$ 3 units left.

Answer

Brief Explanations:

For a function $y = f(x)$, the transformation $y = f(x + a)$ (where $a>0$) results in a horizontal shift of the graph of $y = f(x)$ to the left by $a$ units. Here, $h(x)=\log_6x$ and $m(x)=\log_6(x + 3)$, so we have a left - shift by 3 units.

Answer:

Translate each point of the graph of $h(x)$ 3 units left.