can you show that this quadrilateral is a parallelogram?\nyes\nno
can you show that this quadrilateral is a parallelogram?\nyes\nno
Answer
Explanation:
Step1: Find the 4th interior angle
Sum of quadrilateral angles = $360^\circ$. Let 4th angle = $x$. $x = 360^\circ - (68^\circ + 112^\circ + 68^\circ) = 112^\circ$
Step2: Verify opposite angles congruent
Opposite angles: $68^\circ \leftrightarrow 68^\circ$, $112^\circ \leftrightarrow 112^\circ$.
Step3: Confirm parallelogram criterion
A quadrilateral with all opposite angles equal is a parallelogram.
Answer:
yes