yuto and lian are at train stations 1,880 kilometers apart. yuto boards a train heading east at an average…

yuto and lian are at train stations 1,880 kilometers apart. yuto boards a train heading east at an average speed of 220 kilometers per hour. at the same time, lian boards a train heading west on a parallel track at an average speed of 250 kilometers per hour. how far has lian traveled when the two trains pass each other?\n| | rate (km/h) | time (h) | distance (km) |\n|--|--|--|--|\n| yuto | 220 | t | 220t |\n| lian | 250 | t | 250t |\n470 kilometers\n880 kilometers\n940 kilometers\n1,000 kilometers

yuto and lian are at train stations 1,880 kilometers apart. yuto boards a train heading east at an average speed of 220 kilometers per hour. at the same time, lian boards a train heading west on a parallel track at an average speed of 250 kilometers per hour. how far has lian traveled when the two trains pass each other?\n| | rate (km/h) | time (h) | distance (km) |\n|--|--|--|--|\n| yuto | 220 | t | 220t |\n| lian | 250 | t | 250t |\n470 kilometers\n880 kilometers\n940 kilometers\n1,000 kilometers

Answer

Explanation:

Step1: Set up the equation

Since the sum of their distances equals the total distance between stations, we have $220t + 250t=1880$.

Step2: Combine like - terms

Combining the terms on the left - hand side gives $(220 + 250)t=1880$, so $470t = 1880$.

Step3: Solve for $t$

Dividing both sides by 470, we get $t=\frac{1880}{470}=4$ hours.

Step4: Find Lian's distance

Lian's distance is given by $d = 250t$. Substituting $t = 4$ into the formula, we have $d=250\times4 = 1000$ kilometers.

Answer:

1,000 kilometers