11. nicholas needs to apply 78 pounds of actual phosphorus to his corn field. if he can buy map (11-52-0)…

11. nicholas needs to apply 78 pounds of actual phosphorus to his corn field. if he can buy map (11-52-0) for $450 per ton, what is his cost per acre going to be to apply the needed phosphorus for his corn?a. $17.55b. $22.25c. $33.75d. $43.75e. none of the above$\frac{450}{2000}=0.225 \times 78 = 17.55$

11. nicholas needs to apply 78 pounds of actual phosphorus to his corn field. if he can buy map (11-52-0) for $450 per ton, what is his cost per acre going to be to apply the needed phosphorus for his corn?a. $17.55b. $22.25c. $33.75d. $43.75e. none of the above$\frac{450}{2000}=0.225 \times 78 = 17.55$

Answer

Explanation:

Step1: Find MAP P content fraction

MAP (11-52-0) has 52% phosphorus, so the fraction is $\frac{52}{100}=0.52$.

Step2: Calculate total pounds of MAP needed

To get 78 lbs of phosphorus, divide by the P fraction: $\frac{78}{0.52}=150$ pounds of MAP.

Step3: Convert MAP pounds to tons

Since 1 ton = 2000 pounds: $\frac{150}{2000}=0.075$ tons.

Step4: Calculate total cost per acre

Multiply tons by cost per ton: $0.075 \times 450 = 33.75$

Answer:

c. $33.75